½ñÄê»á¹ÙÍø

dz̸̼ËáÇâÄÆÆ¬ÖÎÁÆÍ´·ç²¡

ʱ¼ä £º2022-08-20 ÔĶÁÁ¿£º19770´Î ·ÖÏí£º

Í´·çÊÇÒ»ÖÖÒÔ¸ßÄòËáѪ֢£¨HUA£©µÄÎªÌØÕ÷µÄ´úлÐÔÑ×Ö¢¼²²¡£¬ £¬£¬£¬£¬£¬µ±ÑªÇåÄòËáŨ¶È£¨SUA£©> 420μmol/Lʱ£¬ £¬£¬£¬£¬£¬ÄòËáÄÆ£¨MSU£©¾§Ìå¿ÉÐγɲ¢³Á»ýÔÚÊàŦ»¬Ä¤¡¢»¬ÄÒ¡¢Èí¹Ç¼°½áµÞ×éÖ¯ÖУ¬ £¬£¬£¬£¬£¬½ø¶ø±¬·¢¼±ÐÔÍ´·çÐÔÊàŦÑ×£¬ £¬£¬£¬£¬£¬Í¬Ê±HUAºÍÍ´·çÒ²ÊÇÂýÐÔÉö²¡¡¢ÐÄÄÔѪ¹Ü¼²²¡¡¢¸ßѪѹ¼°´úлÐÔ¼²²¡µÄ×ÔÁ¦Î£ÏÕÒòËØ¡£¡£¡£¡£¡£

 

 

1661513745134930.jpg

 

 

³ýÄòËáÑÎŨ¶È£¬ £¬£¬£¬£¬£¬PHÖµÒ²ÊÇÓ°ÏìMSU³Á»ýµÄÒòËØÖ®Ò»£¬ £¬£¬£¬£¬£¬PHÖµ½µµÍ¿ÉÔöÇ¿¾§ÌåµÄ³ÉºË·´Ó¦£¬ £¬£¬£¬£¬£¬´Ó¶øÔö½øMSUÔÚÊàŦ²¿Î»µÄ½á¾§£¬ £¬£¬£¬£¬£¬ÄòÒº¼î»¯¿ÉÔöÌíÄòËáÑÎÏûÈÚ¶È£¬ £¬£¬£¬£¬£¬Ôö½øÄòËáÉøÍ¸¡¢±ÜÃâMSU³Á»ý¼°½µµÍÃÚÄòϵÄòËá½áʯµÄ·¢²¡Î£º¦¡£¡£¡£¡£¡£

 

ÁÙ´²ÉϾ­³ £»£»£»£»£»á¸øÍ´·ç»¼Õß¿ªÌ¼ËáÇâÄÆÆ¬¿Ú·þ, ̼ËáÇâÄÆÆ¬³£ÓÃÀ´¼î»¯ÄòÒº£¬ £¬£¬£¬£¬£¬¸¨ÖúÄòËáÏûÈÚ¡¢ÉøÍ¸¡¢½µµÍÉöÔàÄòËá½áʯµÄΣº¦¡£¡£¡£¡£¡£

 

̼ËáÇâÄÆÊdz£ÓÃÇÒ¾­¼Ãʵ»ÝµÄÄòÒº¼î»¯Ò©Î £¬£¬£¬£¬£¬ÓÉÓÚÄòËáÑÎÔÚ¼îÐÔÇéÐÎÏÂÏûÈڶȸߣ¬ £¬£¬£¬£¬£¬¿Ú·þ̼ËáÇâÄÆÆ¬¼î»¯ÄòҺʹµÃÄòÒº³Ê¼îÐÔ£¬ £¬£¬£¬£¬£¬ÄòËáÈÝÒ×Ëæ×ÅÄòÒº±»ÉøÍ¸³öÌåÍ⣬ £¬£¬£¬£¬£¬´Ó¶øµÖ´ï½µµÍѪÖÐÄòËáµÄ×÷Óᣡ£¡£¡£¡£

ÓеÄÈË»áÒÉÎʿڷþ̼ËáÇâÄÆÆ¬ÎªÊ²Ã´¿ÉÒԼÄò񼀯£¿£¿£¿£¿£¿¿Ú·þµÄ̼ËáÇâÄÆ²»ÊǽøÈëθÁËÂ𣿣¿£¿£¿£¿ÖªÊ¶¸æËßÎÒÃǿڷþµÄ̼ËáÇâÄÆÓ¦¸Ã»á±»Î¸ËᣨÑÎËᣩÖкͳɠH2O¡¢NaCl ºÍ CO2 £¬ £¬£¬£¬£¬£¬Ôõô¾Íµ½ÄòÒº£¬ £¬£¬£¬£¬£¬²¢Ê¹µÃÄòÒº¼î»¯ÁË£¿£¿£¿£¿£¿

ËäÈ»£¬ £¬£¬£¬£¬£¬ÎÒÃǵÄ֪ʶÊÇ׼ȷµÄ£¬ £¬£¬£¬£¬£¬¿Ú·þµÄ̼ËáÇâÄÆÈ·ÊµÊǻᱻÎÒÃǵÄθËáËùÖк͡£¡£¡£¡£¡£µ« HCO3- ±»Î¸ËáÖÐµÄ H+ ËùÖк͵Äͬʱ»áʹµÃÌåÄÚµÄ H+ ±»ÏûºÄ¡£¡£¡£¡£¡£ÎÒÃÇÖªµÀÌåÄÚ PH ÊÇά³Ö¶¯Ì¬Æ½ºâµÄ£¬ £¬£¬£¬£¬£¬µ±ÌåÄÚ H+ ±»ÏûºÄ£¬ £¬£¬£¬£¬£¬ÊƱػáÒýÆð»úÌåÏìÓ¦µ÷¶¯£¬ £¬£¬£¬£¬£¬Õâ¾ÍÉæ¼°Á½¸ö¹ØÓÚ»úÌåµÄËá¼îƽºâά³ÖÆðןÜÊÇÖØ×÷ÓõÄø£ºÌ¼Ëáôûø¼°¹È°±õ£°·Ã¸¡£¡£¡£¡£¡£

 

 

1661513821102411.png

 

 

£¨1£©Ì¼ËáôûøµÄÖ÷Òª×÷ÓãºÌ¼ËáôûøÖ÷ÒªÂþÑÜÔÚ½ü¶ËС¹Ü£¬ £¬£¬£¬£¬£¬´ß»¯ CO2+ H2O ÌìÉú H2CO3£¬ £¬£¬£¬£¬£¬H2CO3 Ôò²¿·Ö½âÀëΪ H+ ºÍ HCO3-¡£¡£¡£¡£¡£ÕâÑù£¬ £¬£¬£¬£¬£¬Ò»Ñùƽ³£ÇéÐÎÏ£¬ £¬£¬£¬£¬£¬ÉöСÇòÂ˹ýµÄ HCO3- ÏÕЩËùÓÐÔÚÉöС¹ÜºÍÜöÝ͹ÜÒÔ CO2 ÐÎʽ±»ÖØÎüÊÕ£¬ £¬£¬£¬£¬£¬Í¬Ê±°é H+ ÉøÍ¸£¨ÃÚÇ⣩¡£¡£¡£¡£¡£ÒÔÊÇ£¬ £¬£¬£¬£¬£¬Ì¼ËáôûøÖ÷Òª×÷ÓõÄÒªº¦´Ê¾ÍÊÇ£º´ÙÃÚÇâ¡¢´ÙÖØÎüÊÕ HCO3-¡£¡£¡£¡£¡£

£¨2£©¹È°±õ£°·Ã¸µÄÖ÷Òª×÷Ó㺹Ȱ±õ£°·Ã¸Ö÷ÒªÂþÑÜÓÚ½üÇúС¹ÜºÍÜöÝ͹Ü£¬ £¬£¬£¬£¬£¬Ê¹¹È°±õ£°·±¬·¢ÍѰ±·´Ó¦£¬ £¬£¬£¬£¬£¬ÌìÉú¹È°±Ëá¸ù£¨»á½øÒ»²½±»¹È°±ËáÍÑÇâø×÷ÓÃÌìÉú a- ͪÎì¶þËáºÍ NH4+£©ºÍ NH4+¡£¡£¡£¡£¡£NH4+ ½øÒ»²½Í¨¹ý H-Na תÔ˽øÈëС¹ÜÒº¶ø×îÖÕÉøÍ¸¡¢NH4+ µÄÉøÍ¸Ò²Äܹ»Ôö½ø HCO3-  µÄÖØÎüÊÕ¡£¡£¡£¡£¡£ÒÔÊÇ£¬ £¬£¬£¬£¬£¬¹È°±õ£°·Ã¸Ö÷Òª×÷ÓõÄÒªº¦´Ê¾ÍÊÇ£º´Ù NH4+ ÉøÍ¸¡¢´ÙÖØÎüÊÕ HCO3-¡£¡£¡£¡£¡£

ÒÔÊÇ£¬ £¬£¬£¬£¬£¬µ±¿Ú·þ̼ËáÇâÄÆÊ±£¬ £¬£¬£¬£¬£¬ÓÉÓÚ H+ µÄÏûºÄ£¬ £¬£¬£¬£¬£¬»úÌåΪÁËά³ÖÌåÄÚËá¼îƽºâ£¬ £¬£¬£¬£¬£¬¾Í»áʹµÃÔÚÉöÔà´¦ H+ ºÍ NH4+ ÉøÍ¸ÉøÍ¸ïÔÌ­¡¢ HCO3- µÄÖØÎüÊÕïÔÌ­£¬ £¬£¬£¬£¬£¬ÒÔ´Ë×îÖÕµÖ´ïʹµÃÄòÒº PH Éý¸ß£¨¼î»¯ÄòÒº£©¡£¡£¡£¡£¡£

¼ÈÈ»¼î»¯ÄòÒºÄܹ»Ôö½øÄòËáÑεÄÉøÍ¸£¬ £¬£¬£¬£¬£¬ÄÇôÊDz»ÊÇÄòÒº PH Ô½¸ßÔ½ºÃÄØ£¿£¿£¿£¿£¿ÈôÊDz»ÊÇ£¬ £¬£¬£¬£¬£¬ÄÇôʲôÇéÐÎÏÂÐèÒª¼î»¯ÄòÒº£¬ £¬£¬£¬£¬£¬ÄòÒº PH ¹ý¸ß»áÓÐʲôÎÊÌâÂ𣿣¿£¿£¿£¿

 

 

1661513873808481.png

 

 

ÏÔÈ»£¬ £¬£¬£¬£¬£¬²¢²»ÊÇÄòÒºÔ½“¼î”Ô½ºÃ£¬ £¬£¬£¬£¬£¬ÈôÊÇÄòÒº PH ¹ý¸ß£¬ £¬£¬£¬£¬£¬µ± PH£¾7.0 ʱ£¬ £¬£¬£¬£¬£¬·´¶øÈÝÒ×ÐγɲÝËá¸ÆºÍÁ×ËáÑÎÀàµÈÆäËû½áʯ¡£¡£¡£¡£¡£ÒÔÊÇ£¬ £¬£¬£¬£¬£¬ÔÚ¾ÙÐÐÄòÒº¼î»¯Ê±Òª¼à¿ØÄòÒº PH£¬ £¬£¬£¬£¬£¬Æ¾Ö¤ PH ÖµÀ´µ÷½âÓÃÒ©£¬ £¬£¬£¬£¬£¬½µµÍÓÉÓÚÄòÒº PH ¹ý¸ßÒýÆðµÄÄò·½áʯ¼¸ÂÊ¡£¡£¡£¡£¡£

µ±ÄòÒº PH£¼6.0 ʱ£¬ £¬£¬£¬£¬£¬Ò©ÎïÖÎÁÆÍ¬Ê±Ðè¾ÙÐÐÄòÒº¼î»¯¡£¡£¡£¡£¡£ÐγÉÄòËá½áʯÓÐÁ½¸öÖ÷ÒªÒòËØÊÇ£ºÄòËáÑÎŨ¶È¹ý¸ßºÍÄòÒº³ÊËáÐÔ¡£¡£¡£¡£¡£µ±PHΪ7.0 ʱÄòËáµÄÏûÈÚ¶ÈԼΪ 1.2 mmol/L£¬ £¬£¬£¬£¬£¬¿ÉÊÇÔÚÄòÒº PH Ϊ 5.0 ʱ£¬ £¬£¬£¬£¬£¬ÄòËáµÄÏûÈÚ¶ÈÔò½µÖÁ 0.09 mmol/L¡£¡£¡£¡£¡£Í´·ç²¡ÈËǡǡ֪×ãÕâÁ½¸öÌõ¼þ£¬ £¬£¬£¬£¬£¬ÒÔÊÇÍ´·ç»¼ÕßÈÝÒ×ÐγÉÄòËá½áʯ¡£¡£¡£¡£¡£

 

 

1661513929271917.png

 

 

µ±ÄòÒº PH ÔÚ 6.2-6.9 Ö®¼äʱ£¬ £¬£¬£¬£¬£¬àÑßÊ´úлËù±¬·¢µÄÄòËáÑÎÔڸà PH¹æÄ£ÏûÈÚ¶È´ó£¬ £¬£¬£¬£¬£¬ÈÝÒ×±»ÏûÈÚ£¬ £¬£¬£¬£¬£¬Òò´Ë¿ÉÒÔÔö½øÄòËáÑνᾧÏûÈںʹÓÄòÒºÖÐÇãÔþ¡£¡£¡£¡£¡£

̼ËáÇâÄÆÆ¬ÓÃÓڼÄòÒº¼°ËáѪ֢£¬ £¬£¬£¬£¬£¬Ò²¿ÉÓÃÓÚθËá¹ý¶à¡£¡£¡£¡£¡£Ó÷¨ÓÃÁ¿£¬ £¬£¬£¬£¬£¬¿Ú·þ£¬ £¬£¬£¬£¬£¬³ÉÈË£ºÃ¿´Î 0.25¡«2g£¨0.5¡«4 Ƭ£©£¬ £¬£¬£¬£¬£¬Ò»ÈÕÈý´Î¡£¡£¡£¡£¡£¶ùͯ£º·þÓüÁÁ¿Ó¦×Éѯҽʦ»òҩʦ¡£¡£¡£¡£¡£Í¨³£¹ýÁ¿·þÓÃûÓÐÌ«¶à²»Á¼·´Ó¦£¬ £¬£¬£¬£¬£¬ÈôÓв»Ë³Ó¦Á¬Ã¦Ç°ÍùÒ½Ôº¾ÍÕ £¬£¬£¬£¬£¬Ò½Éú»áÆÀ¹À״̬²¢¾öÒéÈçÄÇÀïÖùýÁ¿·þÓõÄÇéÐΡ£¡£¡£¡£¡£ÈôÊÇÒÅÍü·þҩʱ£¬ £¬£¬£¬£¬£¬Ó¦¾¡¿ì·þÓÃÒ©Æ·¡£¡£¡£¡£¡£µ«ÈôÊÇÒѾ­¿¿½üÏ´ηþҩʱ¼ä£¨Ð¡ÓÚÓÃÒ©¾àÀëµÄ 1/2 £©£¬ £¬£¬£¬£¬£¬Ôò²»±Ø²¹·þ£¬ £¬£¬£¬£¬£¬Æ¾Ö¤Ô­À´Ê±¼ä·þÓÃÏÂÒ»´Î¼ÁÁ¿£¬ £¬£¬£¬£¬£¬ÍòÍò²»¿ÉÒ»´Î·þÓÃÁ½±¶¼ÁÁ¿¡£¡£¡£¡£¡£

 

 

ÍøÕ¾µØÍ¼